若3x+4y+5z=17,3x+2y+z=13,则x+y+z= )
1个回答
两式相加得6x+6y+6z=30
所以x+y+z=30÷6=5
相关问题
若[x/2=y3=z4],且3x-2y+5z=-20,则x+3y-z=______.
若2x+3y+4z=6,3x+2y+z=4,则x+y+z=
2x-y+2z=-17 3x+y-3z=-4 x+y+z=6
若(x-3):(y+4):(2 z+3)=2:3:5 且3x-2y+z=23.则x:y:z=______
(1)2X+4Y+3Z=93X-2Y+5Z=115X-6Y+7Z=13(2)X:Y=3:2Y:Z=5:4X+Y+Z=66
若方程2x+4y+3z=13,3x+y-8z=12 ,则x+y-z的值为
{2x+3y+2z=19{3x+2y+2z=17{2x+2y+3z=13
x+y+z=2 ① 2x+3y+z=38 ① x+y=3 3x-y-4z=5 ② 3x+4y+2z+56 ② y+z=5
{3x-2y+5z=02x+5y-10z=192x+3y+15z=13{x+y=3y+z=5x+z=6
{5x-4y+4z=13 {2x+7y-3z=19 {3x+2y-z=18