Question

计算:2的n+3次方减16乘2的n次方除以2乘2的n+2次方

Answer 1

[2^(n+3)-16*2^n]÷2*2^(n+2)

=[2^(n+3)-(2^4)*2^n]÷2^(n+3)

=[2^(n+3)-2^(n+4)]÷2^(n+3)

=[2^(n+3)-2*2^(n+3)]÷2^(n+3)

=2^(n+3)(1-2)÷2^(n+3)

=-2^(n+3)÷2^(n+3)

=-1