(1)(x^3-2x^2y)/(x^2-2xy^2)=〔x^2(x-2y)〕/〔xy(x-2y)〕=x/y=3
(2)(x^2+2xy+y^2)/(x^2-xy-2y^2)=(x+y)^2/〔(x-2y)(x+y)〕=(x+y)/(x-2y)
由x/y=1/2推出y=2x代入上式得(x+2x)/(x-4x)=-1
(1)(x^3-2x^2y)/(x^2-2xy^2)=〔x^2(x-2y)〕/〔xy(x-2y)〕=x/y=3
(2)(x^2+2xy+y^2)/(x^2-xy-2y^2)=(x+y)^2/〔(x-2y)(x+y)〕=(x+y)/(x-2y)
由x/y=1/2推出y=2x代入上式得(x+2x)/(x-4x)=-1