lim(1/√n-2/√n+3/√n-4/√n+...(2n-1)√n-2n/√n)=?x趋近于无穷
1个回答
lim(1/√n-2/√n+3/√n-4/√n+...(2n-1)√n-2n/√n)
=lim[(1-2+3-4+..+2n-1-2n)/√n]
=lim(-n/√n)
=-lim√n
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