Question

初三数学：二次函数;已知y=a(x-m)2(a≠0）的图像与直线y=2x+1

Answer 1

2x+1=a(x-m)

(2-a)x=-am-1

x=(am+1)/(a-2)=0

am=-1

y=2(am+1)/(a-2)+1=m

2am+2+a-2=am-2m

am+a=-2m

a=-2m+1

m(1-2m)=-1

-2m^2+m+1=0

2m^2-m-1=0

(2m+1)(m-1)=0

m=1或-1/2

a=-1或2