51*51+52*52+53*53+.+99*99=?

1个回答

  • (n-1)²+n²+(n+1)²=3n²+2*1²

    (n-2)²+(n-1)²+n²+(n+1)²+(n+2)²=5n²+2*2²+2*1²=5n²+2*(2²+1²)

    51*51+52*52+53*53+.+99*99

    =(75-24)²+(75-23)²+..+75²+..+(75+23)²+(75+24)²

    =49*75²+2*(24²+23²+.+2²+1²)

    =49*75²+2*(24²+23²+.+2²)+2

    =49*75²+2*[23*13²+2*(11²+10²+1²)]+2

    =49*75²+2*23*13²+4*[11*6²+2*(5²+4²+3²+2²+1²)]+2

    =49*75²+2*23*13²+4*11*6²+8*[5*3²+2*(2²+1²)]+2

    =49*75²+2*23*13²+4*11*6²+8*5*3²+16*5+2

    然后就先算乘法再算加法!

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