dx=2sintcostdt对t求导得cos(t-y)=costcosy+sintsiny对t求导得-sintcosy-costsiny*dy/dt+costsiny+sintcosy*dy/dtdy/dt*sint+y*cost+sintcosy+costsiny*dy/dt-costsiny-sintcosy*dy/dt=0所以dy/dt=(costsiny-sintcos...
高数1的题目求导计算,为了补考,分不多,表心意
dx=2sintcostdt对t求导得cos(t-y)=costcosy+sintsiny对t求导得-sintcosy-costsiny*dy/dt+costsiny+sintcosy*dy/dtdy/dt*sint+y*cost+sintcosy+costsiny*dy/dt-costsiny-sintcosy*dy/dt=0所以dy/dt=(costsiny-sintcos...