Question

已知直线y=-2x+3与直线y=x-6交于点a,且两直线与x轴的交点分别为b.c,求三角形abc的面积

Answer 1

当y=0时,-2x+3=0 x=3/2 b=3/2

当y=0时,x-6=0 x=6 c=6

-2x+3=x-6

3x=9

x=3

y=3-6=-3

a=|-3|=3

S△=(1/2)*|6-(3/2)|*3

=(3/2)*(9/12)

=27/24

=9/8