(x^2-6x+9)÷x^2-9x+18/x+3
1个回答
(x^2-6x+9)÷x^2-9x+18/x+3
=(x-3)^2÷(x+3)(x-3)+18/(x+3)
=(x-3)/(x+3)+18/(x+3)
=(x+15)/(x+3)
相关问题
若x=3/x,则[(x^2-6x+9)/(x+3)]÷[﹙x-3﹚/﹙x^2+6x+9﹚]=?
3x-2=1.6 5x÷2=25 x-18=2.9+0.71 8x+x=
(1-x/3-x)^2÷(x^2-6x+9/9-x^2)*1/x^2-2x+1
9 ÷ 3(2+1) 9 ÷ 3(2+1) = 9 ÷(3x2+3x1)= 9 ÷ (6+3) = 9÷9 = 1
解分式方程,化简1.1/X-2=3/X2.X^-6X+9/9-X^2÷2X-6/X^2+3X
(x-3)(x-2)+18=(x+9)(x+1) 解:x²-5x+6+18=x²+10x+9 15x
(9x³-6x²-5x+2﹚÷﹙3x-1﹚=?
2x÷(x^2-9) + 1÷(3-x) + (x+2)÷(x+3)=?
(2x-6)/(x²-4x+4)÷(3-x)/(x²+6x+9)×(2-x)/(x+3)