Question

数学题.关系分式.急若1、b分之a=3,求a+3b分之2a-3b2、x^21分之x^3+x^2+x+1x^3+1 分之

Answer 1

1. 由a/b=3可得a=3b

(a+3b)/(2a-3b)=(3b+3b)/(6b-3b)=6b/3b=2

2. x^21/x^3+x^2+x+1

=x^(21-3)+x^2+x+1

=x^18+x^2+x+1