2x(x-1)-(3x+2)x+2x^2=x^2+

2x(x-1)-(3x+2)x+2x^2=x^2+1

1个回答

1.(x^3-1)/(x^3+2x^2+2x+1)+(x^3+1)/(x^3-2x^2+2x-1)-(2x^2+2)/(
1-[2x^3/x-1-(x^2+x+1)]*x^2-1/(x-1)^2+x除以(x^2-2x-3)
1X2=1/3（1X2X3-0X1X2) 2X3=1/3(2X3X4-1X2X3) 发现1X2+2X3+3X4+、、、、
(2x-3)(2x+3) (3x-1)^2 （-2X）(3X^2-2X+1) (2X-3)(3X+2) (X-2)(X+
三阶矩阵 [1,1,1；x1,x2,x3; x1^2,x2^2,x3^2]=(x2-x1)(x3-x1)(x3-x2)是
1.3x（x-2)=x-2 2.（2x-1)²-2（2x-1)=3 3.（x²-5x+1）（x&su
因式分解(2x+1)²(3x-2)-(2x+1)(3x-2)²-x(2x-1)(2-3x) 其中x=
｛2X1-X2+3X3=33X1+X2-5X3=04X1-X2+X3=3X1+3X2-13X3=-6{X1-2X2+3X
（1）积分x^3/(1+x^2)^(1/2) (2)积分（x^3+x^2+2x+1)/(x^2+1)(x^2+2)
1/(2-x)²,x/x²-4 1/3x(x-2),1/(x-2)(x+3),1/2(x+3)