答:
f(x+y)=f(x)+f(y)+1;f(1)=2
所以:
f(3)=f(1+2)
=f(1)+f(2)+1
=2+f(2)+1
=3+f(1+1)
=3+f(1)+f(1)+1
=4+2+2
=8
所以:f(3)=8