(lg5)^2 +2(lg)^2 +1-(lg2)^2
1个回答
=lg²5-lg²2+2lg2
=(lg5+lg2)×(lg5-lg2)+2lg2
=lg5-lg2+2lg2
=lg5+lg2
=1
相关问题
lg2^2+lg2*lg5+lg5=lg2(lg2+lg5)+lg5
(lg2)2[2lg5+1]+(lg5)2[2lg2+lg10]
(lg5)^2+lg2lg50+2^((1+1/2(log2(5))))=2+2√5?=(1-lg2)^2+lg2lg1
1.lg²5+lg2×lg5+lg2 2.(lg2)³ +(lg 5)³ +3lg 2×l
如何将(lg2)²+(2lg2+lg5)×lg5变成(lg2)2+2lg2lg5+(lg5)²
1/2(lg2)^2+1/2lg2*lg5+√1/4(lg2)^2-lg2+1=?
1、lg5^2+2/3lg8+lg5lg20+(lg2)^2
(lg2-lg5)/(2lg2-lg5)=?取lg2=0.3 为什么上式=(1-2lg2)/(1-3lg2)?
(2lg5·2lg2·2lg3)/(lg5·lg2·lg3)=
2lg2×﹙lg2+lg5﹚+2lg5为什么等于2lg2+2lg5