Question

若a2-3a+1=0,则2a5-5a4+2a3-8a2+3a+3=?很急、有木有人会、要有过程哈

Answer 1

2a^5-5a^4+2a^3-8a^2+3a+3

=2a^5-6a^4+2a^3+a^4-3a^3+a^2+3a^3-9a^2+3a+3

=2a^3(a^2-3a+1)+a^2(a^2-3a+1)+3a(a^2-3a+1)+3

=0+0+0+3

=3