Question

26.(8分)将6.50 g锌投入200 mL某浓度的盐酸中,锌和盐酸恰好完全反应.

Answer 1

设盐酸中HCl的物质的量浓度为c(HCl),

n(Zn)=m(Zn)/M(Zn)=6.50g/65g/mol=0.1mol

Zn + 2HCl===ZnCl2+H2↑

1 2

0.1mol c(HCl)×0.2L

1mol/0.1mol=2mol/c(HCl)×0.2L

c(HCl)=1mol/L