(1+i)^17=(1+i)^2×(1+i)^2×...×(1+i)^2×(1+i)【(1+i)^2项共8个】因为(1+i)^2=1^2+i^2+2i=2i所以(1+i)^17=2i×2i×...2i×(1+i)=256+256i同理(1-i)^17=(1-i)^2×(1-i)^2×...×(1-i)^2×(1-i)【(1-i)^2项共8个】...
复数的加减法[(1+i)^17+(1-i)^17]/[(1+i)^16+(1-i)^16]
(1+i)^17=(1+i)^2×(1+i)^2×...×(1+i)^2×(1+i)【(1+i)^2项共8个】因为(1+i)^2=1^2+i^2+2i=2i所以(1+i)^17=2i×2i×...2i×(1+i)=256+256i同理(1-i)^17=(1-i)^2×(1-i)^2×...×(1-i)^2×(1-i)【(1-i)^2项共8个】...