设原来乙书有x本,则甲书有﹙5/4﹚x,得
7/4﹙x-112﹚=﹙5/4﹚x-112
7/4x-196 =5/4x-112
7/4x-5/4x=﹣112+196
1/2x=84
x=168
﹙5/4﹚x=5/4×168=210
答:原来乙书有168本,则甲书有210本.
设原来乙书有x本,则甲书有﹙5/4﹚x,得
7/4﹙x-112﹚=﹙5/4﹚x-112
7/4x-196 =5/4x-112
7/4x-5/4x=﹣112+196
1/2x=84
x=168
﹙5/4﹚x=5/4×168=210
答:原来乙书有168本,则甲书有210本.