数学暑假作业要提取公因式10题,公式法10题,分组分解法10题,十字相乘法10题,-

2个回答

  • 1)x9+x6+x3-3;

    (2)(m2-1)(n2-1)+4mn;

    (3)(x+1)4+(x2-1)2+(x-1)4;

    (4)a3b-ab3+a2+b2+1.

    解 (1)将-3拆成-1-1-1.

    原式=x9+x6+x3-1-1-1

    =(x9-1)+(x6-1)+(x3-1)

    =(x3-1)(x6+x3+1)+(x3-1)(x3+1)+(x3-1)

    =(x3-1)(x6+2x3+3)

    =(x-1)(x2+x+1)(x6+2x3+3).

    (2)将4mn拆成2mn+2mn.

    原式=(m2-1)(n2-1)+2mn+2mn

    =m2n2-m2-n2+1+2mn+2mn

    =(m2n2+2mn+1)-(m2-2mn+n2)

    =(mn+1)2-(m-n)2

    =(mn+m-n+1)(mn-m+n+1).

    (3)将(x2-1)2拆成2(x2-1)2-(x2-1)2.

    原式=(x+1)4+2(x2-1)2-(x2-1)2+(x-1)4

    =〔(x+1)4+2(x+1)2(x-1)2+(x-1)4]-(x2-1)2

    =〔(x+1)2+(x-1)2]2-(x2-1)2

    =(2x2+2)2-(x2-1)2=(3x2+1)(x2+3).

    (4)添加两项+ab-ab.

    原式=a3b-ab3+a2+b2+1+ab-ab

    =(a3b-ab3)+(a2-ab)+(ab+b2+1)

    =ab(a+b)(a-b)+a(a-b)+(ab+b2+1)

    =a(a-b)〔b(a+b)+1]+(ab+b2+1)

    =[a(a-b)+1](ab+b2+1)

    =(a2-ab+1)(b2+ab+1).