(1)原式=x^2(x^2-4x+1)+2x^3-9x^2+6x+2012
=2x(x^2-4x+1)-x^2+4x+2012
=-(x^2-4x+1)+2013
=2013
(2)由x^2-4x+1=0两边同除以x可得x+1/x=4
两边平方x^2+1/x^2+2=16即x^2+1/x^2=14
原式=5(x^2-4x+1)+8x-5+2/x^2
=2(4x-1)-3+2/x^2
=2x^2+2/x^2-3
=2*14-3
=25
(1)原式=x^2(x^2-4x+1)+2x^3-9x^2+6x+2012
=2x(x^2-4x+1)-x^2+4x+2012
=-(x^2-4x+1)+2013
=2013
(2)由x^2-4x+1=0两边同除以x可得x+1/x=4
两边平方x^2+1/x^2+2=16即x^2+1/x^2=14
原式=5(x^2-4x+1)+8x-5+2/x^2
=2(4x-1)-3+2/x^2
=2x^2+2/x^2-3
=2*14-3
=25