计算:{x√x+x√y / xy-y²}-{x+√xy+y / x√x-y√y}
2个回答
原式=x(√x+√y)/y(√x+√y)(√x-√y)-(x+√xy+y)/(√x-√y)(x+√xy+y)
=x/y(√x-√y)-y/y(√x-√y)
=(√x+√y)/y
相关问题
分式计算:(x²+2xy+y²)/(x²y+xy)*y/(x+y)
(x^2+xy/x-y)/(xy/x-y)计算
计算:(xy-x²)÷[(x²-2xy+y²)/xy]•(x-y)/(x²)
计算(x-y)(x平方+xy+y平方)-(x+y)(x平方-xy+y平方)
(x+y)(x²-xy+y²),(x-y)(x²+xy+y²)
一道含有根号的计算题(字母)计算 (x*√x+x*√y)/(xy-y²)-(x+√xy+y)/(x*√x-y*√y)√是
作乘法:(x+y)(x²-xy+y²),(x-y)(x²+xy+xy+y²).(
(x-y)²(x+y)²(x²-xy+y²)²(x²+xy+
有这样一道题,计算:(x﹣y)[(x+y) 2 ﹣xy]﹣(x﹣y)[(x﹣y) 2 +xy]﹣2xy(x﹣y)+3x
计算 ①[x(x²y²-xy)-y(x²-x³y)]÷3x²y