Question

在同一平面直角坐标系中画出函数y=2x与y=—2x+8的图像,并依据它们的图像回答问题

Answer 1

1. y = 0时,-2x+8 = 0, x = 4, A(4, 0）

2. 联立：2x = -2x +8, x =2, y = 4, P(2, 4)

3. △POA的面积 = (1/2)*OA*P的纵坐标= (1/2)*4*4 = 8

4. OP = √(2²+4²) = 2√5

AP = √[(4-2)²+(0-4)²] = 2√5

OP = AP

等腰三角形