Question

求复合函数解析式1.已知f(x-2)=2x'2(2倍x的2次方)-9x+13求f(x)解析式2.已知2f(x)+f(-x

Answer 1

1.x-2=t,x=t+2

f(t)=2(t+2)^2-9(t+2)+13=2t^2-t+3

2.

2f(x)+f(-x)=3x+2

2f(-x)+f(x)=-3x+2

f(x)/2+f(-x)=-3x/2+1

1.5f(x)=4.5x+1

f(x)=3x+2/3