两种相似情况
(1)简单得CP=4
则t=4/5
(2)
因为PB=PO
BH=5
BH:BA=BP:BO
5:6=BP:10
BP=PO=25/3
CP=5/3
t=5/3 除以5=1/3
2.
OHP~BAO
设CP=5t
OP=10-5t
OP:OB=OH:BA
(10-5t):10=OH:6
OH=6-3t
同理可得HP=8-4t
且BH=10-(6-3t)=3t+4
则S=(3t+4)*(8-4t)/2
=-6t^2+4t+16
=-6(t-1/3)^2+50/3
当t=1/3时有最大值