1.(300 - 40*1.5)/(40 + 80) = 2
2.该队总共要比赛11场,其中设X场负,则X+2场胜,11-2X-2场为平,即 X*0 + 3(X+2) + 1(9-2X)= 18
解得 X = 3
3.设原速度为X,则 9X - 50 =(X+40)* 6
解得X = 290/3
则改道后路程为 290/3 * 9 -50 = 820
1.(300 - 40*1.5)/(40 + 80) = 2
2.该队总共要比赛11场,其中设X场负,则X+2场胜,11-2X-2场为平,即 X*0 + 3(X+2) + 1(9-2X)= 18
解得 X = 3
3.设原速度为X,则 9X - 50 =(X+40)* 6
解得X = 290/3
则改道后路程为 290/3 * 9 -50 = 820