=1*(2+1)(2^2+1)(2^4+1).(2^32+1)+2
=(2-1)*(2+1)(2^2+1)(2^4+1).(2^32+1)+2
=(2^2-1)(2^2+1)(2^4+1).(2^32+1)+2
=(2^4-1)(2^4+1).(2^32+1)+2
反复运用平方差
=(2^64-1)+2
=2^64+1
2末尾2
2^2末尾4
2^3末尾8
2^4末尾6
2,4,8,6循环
64÷4没有余数,所以2^64末尾是6
所以2^64+1末尾是7
=1*(2+1)(2^2+1)(2^4+1).(2^32+1)+2
=(2-1)*(2+1)(2^2+1)(2^4+1).(2^32+1)+2
=(2^2-1)(2^2+1)(2^4+1).(2^32+1)+2
=(2^4-1)(2^4+1).(2^32+1)+2
反复运用平方差
=(2^64-1)+2
=2^64+1
2末尾2
2^2末尾4
2^3末尾8
2^4末尾6
2,4,8,6循环
64÷4没有余数,所以2^64末尾是6
所以2^64+1末尾是7