)如图,矩形OABC中,点O为原点,点A的坐标为(0,8),点C的坐标为(6,0).

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  • (1)证明:∵∠ACD=∠BCE,∴∠ACD+∠DCE=∠BCE+∠DCE,∴∠ACE=∠DCB,又∵CA=CD,CE=CB,∴△ACE≌△DCB. (2)△AMC∽△DMP. 理由:∵△ACE≌△DCB,∴∠CAE=∠CDB,又∵∠AMC=∠DMP,∴△AMC∽△DMP. (3)∵△AMC∽△DMP,∴MA:MD=MC:MP. 又∵∠DMA=∠PMC,∴△AMD∽△CMP,∴∠ADC=∠APC. 同理∠BEC=∠BPC. ∵CA=CD,CB=CE,∴∠ADC= (180°-∠ACD),∠BEC= (180°-∠BCE). ∵∠ACD=∠BCE,∴∠ADC=∠BEC,∴∠APC=∠BPC.