log(a/b)[c]
=1/{log(c)[a/b]}
而:
log(c)[a/b]=log(c)[a]-log(c)[b]
. =1/{log(a)[c]}-1/{log(b)[c]}
. =(1/x1)-(1/x2)
则:
log(a/b)[c]=1/[(1/x1)-(1/x2)]=(x1x2)/(x2-x1)
log(a/b)[c]
=1/{log(c)[a/b]}
而:
log(c)[a/b]=log(c)[a]-log(c)[b]
. =1/{log(a)[c]}-1/{log(b)[c]}
. =(1/x1)-(1/x2)
则:
log(a/b)[c]=1/[(1/x1)-(1/x2)]=(x1x2)/(x2-x1)