Question

初一数学题.`关于补角与余角.~~

Answer 1

因为"角A与角B互为余角"

所以∠A+∠B=90

因为"角A与角C互为补角"

所以∠A+∠C=180

则∠B+∠C=90+180-2∠A

=270-2∠A

所以∠B+∠C/360=270-2∠A/360

∠A+∠B+∠C

=∠A+∠B+(180-∠A)

=∠B+180

=90-∠A+180

=270-∠A