lim(x→0,y→0) (sinxy/2x)=
1个回答
lim(x→0,y→0) (sinxy/2x)
=lim(x→0,y→0) (siny/2)
=sin0
=0
相关问题
lim(x->0 y->a)sinxy/x的计算过程
大家看看有什么区别lim lim [(x^2-y^2)/(x^2+y^2)]y-0 x-0lim lim [(x^2-y
证明下列极限不存在(1) Lim x+y/x-y (2)lim x²y²/ x²y²+(x-y)²(x,y)→(0,0)
讨论极限lim(x→0 y→0) [(X^2)y]/[(x^4)+(y^2)]:
【高数】y=|sinx|,lim(x→0)=|sin0|=0 和 lim(x→0)=(|sinx|-0)/x-0=lim
maple12使用问题用maple解 二元函数的极限 怎样输入,例如:lim :x/(sinxy) (x→0,y→5)我
1,lim(x,y)→(0,0)xy/2-√(4-xy) 2,lim(x→0)1/x^2∫(0→x)(e^t-1)dt
证明lim(x,y)→(0,0) (x+2y)/(2x-y)极限不存在
求证明极限lim(x,y)->(0,0) (x^2 * sin^2y)/x^2 +9y^2 =0
设函数f(x,y)=x^2y^2/x^4+y^4,(x,y)≠(0,0),则lim(x,y)→(0,0)f(x,y)=