题目应该是sin(x+π/4),否则无法化简
cos2x/sin(x+π/4)
=[(cosx)²-(sinx)²]/[√2/2sinx+√2/2cosx]
=√2[(cosx)²-(sinx)²]/[sinx+cosx]
=√2(cosx-sinx)
=√2/2
题目应该是sin(x+π/4),否则无法化简
cos2x/sin(x+π/4)
=[(cosx)²-(sinx)²]/[√2/2sinx+√2/2cosx]
=√2[(cosx)²-(sinx)²]/[sinx+cosx]
=√2(cosx-sinx)
=√2/2