一道三角函数求和题cosπ/13+cos3π/13+cos9π/13

1个回答

  • 这题难了,一般和差化积貌似不行的:

    已知(或容易求):

    cos(π/13)+cos(3π/13)+...+cos(11π/13)=1/2

    cos(2π/13)+cos(4π/13)+...+cos(12π/13)=-1/2

    令:m=cos(π/13)+cos(3π/13)+cos(9π/13)

    n=cos(5π/13)+cos(7π/13)+cos(11π/13)

    则:m+n=1/2

    经过复杂但不难理解的推导可得:

    m*n=(3/2)(cos(2π/13)+cos(4π/13)+...+cos(12π/13))=-3/4

    解方程组:m+n=1/2和m*n=-3/4

    得:m=(1+√13)/4

    还有一个m=(1-√13)/4要舍去