Question

(1 跟号2)x^2-(1-跟号2)x=0怎么解怎么解?

Answer 1

(1 跟号2)x^2-(1-跟号2)x=0,是不是(1 +跟号2)x^2-(1-跟号2)x=0

若是的话,x【(1+ 跟号2)x-(1-跟号2)】=0

那就是分情况了,当x=0时,方程恒成立；当x不为0时,(1+ 跟号2)x-(1-跟号2）=0,所以x=2根号2-3