∵ log_b (A) + log_b (B) - log_b (C) = nlog_b (x)
∴ log_b [(AB)/C]=nlog_b (x)
∴ log_b (x)=(1/n)·log_b [(AB)/C]
∴ log_b (x)=log_b [(AB)/C]^(1/n)
∴ x= [(AB)/C]^(1/n)
Solve for x in terms of n,A,B,C of log_b (A) + log_b (B) - l
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