sina>√3cosa
sina-√3cosa>0
2sin(a-π/3)>0
sin(a-π/3)>0
因为0≤a<2π所以-π/3≤a-π/3<5π/3
故-π/3≤a-π/3<0或π<a-π/3<5π/3
所以0≤a<π/3或4π/3<a<2π
即a的取值范围是{a|0≤a<π/3或4π/3<a<2π}
如果不懂,请追问,祝学习愉快!
以上回答你满意么?
sina>√3cosa
sina-√3cosa>0
2sin(a-π/3)>0
sin(a-π/3)>0
因为0≤a<2π所以-π/3≤a-π/3<5π/3
故-π/3≤a-π/3<0或π<a-π/3<5π/3
所以0≤a<π/3或4π/3<a<2π
即a的取值范围是{a|0≤a<π/3或4π/3<a<2π}
如果不懂,请追问,祝学习愉快!
以上回答你满意么?