Question

函数f(x)=2x的平方+(x-1)|x-1|的最小值

Answer 1

①当x>=1时

f(x)=2x^2+(x-1)^2=2x^2+x^2+1-2x

=3x^2-2x+1

=3(x^2-2/3x+(2/6)^2-(2/6)^2)+1

=3(x-2/6)^2+2/3

因为x>=1

所以最小值为

f(1)=2

②当x