Question

设函数f(x)=1/3x^3-1/2ax^2+(a^2-3)x+1.(1)若函数f(x)在R上是增函数,求实数a的取

Answer 1

1)f'(x)=x^2-ax+a^2-3,在R上为增函数,则f'(x)恒大于等于0

得：delta=a^2-4(a^2-3)=-3a^2+12=2,或a0,得：-2