(x^1/2)/(x+x^1/2+1)÷(1)/(x^3/2-1)怎样化简?(详细一点)
2个回答
原式=(x^1/2)/(x+x^1/2+1)/1/[(x^1/2-1)(x+x^1/2+1)]
=(x^1/2)(x^1/2-1)
=x-(x^1/2)
相关问题
化简 (x2-2x+1/x2-1)÷﹙1+(x-3/x+1)
化简(1+1/x-1)÷x/x^2-1=?计算(x^2/x-1)-x=?化简1-3a/2b÷3a/2b*2b/3a=?计
先化简(2x-1)²-(3x+1)(3x-1)+20x³(x-1)÷(-2x)²
化简:(1-1/x)÷(x²-2x+1)/x
化简:〔1-[2/(x+1)]〕÷[1/(x²-1)]
化简[1-2/(x+1)]÷1/(x²-1)
化简求值 (3/x-1 -x-1)÷ x-2/x^2-2x+1,其中x=-√2
先化简:(x2+1x2−1-[x+1/x−1])÷[2x(x−1)(x2+2x+1)
(2011•中山区一模)化简:x2−3xx−3÷x2−1x+1−1x−1.
(1)化简:(4x2−4+1x+2)÷1x−2