Question

计算：(a+b+c)^2m（a-b-c）^2m+1（c-a-b)^4m+3（c+b-a）^m+1

Answer 1

（a＋b－c）^2m（a－b－c）^2m+1（c-a-b）^4m+3（c+b-a）^m+1

=(a+b-c)^2m·[-(b+c-a)]^2m+1·[-(a+b-c)]^4m+3·(b+c-a)^m+1

=[-(a+b-c)^6m+3][-(b+c-a)^3m+2

=-(a+b-c)^6m+3·(b+c-a)^3m+2