x+2y+4y^2/(x-2y)=((x+2y)(x-2y))/(x-2y)+4y^2/(x-2y)=(x^2-4y^2)/(x-2y)+4y^2/(x-2y)=x^2/(x-2y) 或者是你的题说的有歧义
x+2y+4x^2y/4y^2+4y^2/x-2y
1个回答
相关问题
-
x+2y+4y^2/x-2y+4x^2y/4y^2-x^2=
-
(16x^4+y^4)(4x^2+y^2)(2x-y)(2x+y)
-
若x/x-1=y^2+4y-1/y^2+4y-2,y^2+4y-x=
-
[x^2-y^2(x-4y)(x+4y)-x^2-y^2(x-2y)^2]/[-(2xy)^2]
-
计算(x-2y)^2-4(2x+y)(y-2x)+4x(y-2)
-
x^2+4y^2-6x+4y+10=0,求x^4-y^4/(x+2y)(x-2y)*x+2y/xy^2+y^3除以(x^
-
已知x^2+4y^2-4x+4y+5=0,求(x^4-y^4/2x^2+xy-y^2)*(2x-y/xy-y^2)/(x
-
已知[(x2+y2)-(x-y)2+2y(x-y)]÷4y=1,求[4x4x2−y2
-
已知[(x2+y2)-(x-y)2+2y(x-y)]÷4y=1,求[4x4x2−y2
-
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&