g(X)=cos(2x-π/2)=sin[π/2-(2x-π/2)]=sin(-2x+π),所以对f(x),先对y轴作对称变换,
得,f '(x)=sin(-2x+π/2).再设f '(x)经过左右平移b,即sin[-2(x+b)+π/2]=sin(-2x+π),得b= -π/2,
所以f '(x)又向右平移了π/2个单位.综述f(x)的图像先对y轴作对称变换,然后向右平移π/2个单位,就得到g(x)的图像.
g(X)=cos(2x-π/2)=sin[π/2-(2x-π/2)]=sin(-2x+π),所以对f(x),先对y轴作对称变换,
得,f '(x)=sin(-2x+π/2).再设f '(x)经过左右平移b,即sin[-2(x+b)+π/2]=sin(-2x+π),得b= -π/2,
所以f '(x)又向右平移了π/2个单位.综述f(x)的图像先对y轴作对称变换,然后向右平移π/2个单位,就得到g(x)的图像.