A=45°
sinA=cosB=√2/2
cosB=4/5
sinB=√(1-cos^2B)=3/5
cosC=cos(180-(A+B))=-cos(A+B)=-cosAcosB+sinAsinB
=-√2/2*4/5+√2/2*3/5
=-√2/10
A=45°
sinA=cosB=√2/2
cosB=4/5
sinB=√(1-cos^2B)=3/5
cosC=cos(180-(A+B))=-cos(A+B)=-cosAcosB+sinAsinB
=-√2/2*4/5+√2/2*3/5
=-√2/10