(1)△ACD≌△AC1D DC1⊥AB,BC=√(5²-3²)=4
∴CD=C1D,AC=AC1,C1B=5-3=2
C1D²=CD²=DB²-2²=(4-CD)²-4
∴CD=3/2
∴AD=√[3²+(3/2)²]=3√5/2
(2)y=AP*DC1/2=3x/4 (0
(1)△ACD≌△AC1D DC1⊥AB,BC=√(5²-3²)=4
∴CD=C1D,AC=AC1,C1B=5-3=2
C1D²=CD²=DB²-2²=(4-CD)²-4
∴CD=3/2
∴AD=√[3²+(3/2)²]=3√5/2
(2)y=AP*DC1/2=3x/4 (0