这道题应该根据PG和PQ共线来解
PG=PA+AG
=OA-OP+AC
=-am+1/3a+1/3b
PQ=OQ-OP
=nb-ma
∴PG=μPQ
μ·(nb-ma)=-am+1/3a+1/3b
kn=1/3.①
km=m-1/3.②
∴m=3mn-n
即1/m+1/n=3
这道题应该根据PG和PQ共线来解
PG=PA+AG
=OA-OP+AC
=-am+1/3a+1/3b
PQ=OQ-OP
=nb-ma
∴PG=μPQ
μ·(nb-ma)=-am+1/3a+1/3b
kn=1/3.①
km=m-1/3.②
∴m=3mn-n
即1/m+1/n=3