(1)n(O 2)=
0.1344L
22.4L/mol =0.006mol,
一份中:n(CaO 2•nH 2O)=2n(O 2)=0.012mol,
n(CaCO 3)=
1.40g
100g/mol =0.014mol,
n(CaO)=n(CaCO 3)-n(CaO 2•nH 2O)=0.002mol,
2.168g样品中m(CaO)=0.002mol×56g/mol×2=0.224g,
答:2.168g样品中CaO的质量为0.224g,
(2)2.168g过氧化钙样品中的质量为2.168g-0.224g,
则2×0.012×(72+18n)=2.168-0.224,
n=0.5,
答:样品中CaO 2•nH 2O的n值为0.5.