Question

函数 f(x)=x(x-m)^2在x=2 处有极大值,则常数m的值

Answer 1

∵f(x)=x(x-m)^2在x=2 处有极大值

∴==>f'(x)=(x-m)^2+2x(x-m)=0

又∵x=2,

∴f'(2)=(2-m)^2+2*2(2-m)=0

==>m=2,or,m=6;

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