[(x-y/2)^2-(x+y/2)^2]÷(-1

[(x-y/2)^2-(x+y/2)^2]÷(-1/2xy).

1个回答

[(x-y/2)^2-(x+y/2)^2]÷(-1/2xy)
=[x²-xy+y²/4-x²-xy-y²/4]÷(-1/2xy)
=-2xy÷(-1/2xy)
=4

[(x+y)^2-(x-y)^2]÷(1/2xy)
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