Question

aˆ4-2aˆ2bˆ3+bˆ6因式分解 求详解

Answer 1

=a^4-a^2b^3-a^2b^3+b^6

=(a^4-a^2b^3)-(a^2b^3-b^6)

=a^2(a^2-b^3)-b^3(a^2-b^3)

=(a^2-b^3)(a^2-b^3)

=(a^2-b^3)^2