Question

已知:丨2a-3b+2丨+(4a-b-1)^2=0,求a,b的值

Answer 1

丨2a-3b+2丨>=0 (4a-b-1)^2>= 0 丨2a-3b+2丨+(4a-b-1)^2=0

丨2a-3b+2丨=0 (4a-b-1)^2=0 2a-3b+2=0 4a-b-1=0 a=1/2 b=1