Question

log2(根号下7/48)+log2(12)-1/2log2(42)-1=?

Answer 1

log2[根号下(7/48)]+log2(12)-1/2log2(42)-1?

=log2{12*根号下(7/48)/[根号下(42)]}-1

=log2{12*根号下[7/(48*42)]}-1

=log2{12*根号下[7/(6*2*2*2**6*7)]}-1

=log2根号下(1/2)-1

=(1/2)log2(1/2)-1

=(1/2)log2(2^-1)-1

=(-1)(1/2)log2(2)-1

=-1/2-1

=-3/2