a^(x-z+m)b^3与b^ma是同类项
则:m=3,x-z+m=1
x-z=-2
(y-z-2)^2+|n-2|=0
y-z=2,n=2
x-y=(x-z)-(y-z)=-2-2=-4
1/2[(x-y)的m-1方+(y-z)的n方+(z-x)的平方]
=1/2[(-4)^2+2^2+2^2]
=24/2
=12
a^(x-z+m)b^3与b^ma是同类项
则:m=3,x-z+m=1
x-z=-2
(y-z-2)^2+|n-2|=0
y-z=2,n=2
x-y=(x-z)-(y-z)=-2-2=-4
1/2[(x-y)的m-1方+(y-z)的n方+(z-x)的平方]
=1/2[(-4)^2+2^2+2^2]
=24/2
=12